Author Topic: HuCard (Who Card or Hugh Card) You decide!  (Read 2869 times)

Arkhan

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Re: HuCard (Who Card or Hugh Card) You decide!
« Reply #60 on: February 14, 2017, 08:39:32 AM »
I only knew about the ROMUROMU pronunciation because of how SuperDeadite would talk about it with the LD-ROM2 games.  Interesting to learn about the W, never really that that fully explained. 

The other unique one Deadite mentioned was how Peke can mean X and it can be used to refer to the X68000. 

most of my friends call it the X rokumanhassen.

They're literally just calling it the X68000 in Japanese at that point, lol.


Its really funny to hear it when they talk about it.    Its also funny to talk to some of them about how they yearned super hard for Amigas even though they had X68000s.    They wanted it more for computational/3D/Fancy stuff though.

I'd imagine, if the Amiga was unleashed in Japan and Japanese developers got to work with it, maybe the library wouldn't be a hodgepodge of shitty wannabe Valis style games.
[Fri 19:34]<nectarsis> been wanting to try that one for awhile now Ope
[Fri 19:33]<Opethian> l;ol huge dong

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schadenfreude

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Re: HuCard (Who Card or Hugh Card) You decide!
« Reply #61 on: February 14, 2017, 08:48:26 AM »
That sum would really be (R + O + M)^2.

You never know — maybe they only wanted to square the memory.

Arkhan

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Re: HuCard (Who Card or Hugh Card) You decide!
« Reply #62 on: February 14, 2017, 11:20:28 AM »
That sum would really be (R + O + M)^2.

You never know — maybe they only wanted to square the memory.

it wouldn't be (R + O + M)2, though.  You can't just add plus signs to things because you feel like it.   The absence of an operator implies multiplication.   The absence of exponents implies there's a power of 1.

So,
(ROM)2 (using exponent rule) is: R2O2M2.   You just take each term and distribute the exponent in.   So R1*2O1*2M1*2

But, this assumes you treat R O and M as three separate variables.

If you assume it's one single variable ie: ("ROM")2, you would get ROMROM.

Which is what the Japanese did.
[Fri 19:34]<nectarsis> been wanting to try that one for awhile now Ope
[Fri 19:33]<Opethian> l;ol huge dong

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MisterCrash

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Re: HuCard (Who Card or Hugh Card) You decide!
« Reply #63 on: February 14, 2017, 11:49:33 AM »

Although going by the above logic, CD ROM ROM should really be CD WROM.  Since ROM2 would really be R*R+R*O+R*M+R*O+O*O+O*M+R*M+O*M+M*M.

Sorry I wasn't clearer. My response was to ccovell (quoted above) noting that the sum he cited was really equivalent to (R + O + M)^2. As you point out, it's not the same as (ROM)^2.

ccovell

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Re: HuCard (Who Card or Hugh Card) You decide!
« Reply #64 on: February 14, 2017, 11:56:28 AM »
My point was that they're words (sequences of syllables or letters), and so mathematical rules cannot possibly apply in a logical way.  Yet the Japanese try.

Punch

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Re: HuCard (Who Card or Hugh Card) You decide!
« Reply #65 on: February 14, 2017, 01:19:23 PM »
I'll start calling the PCE cd rom^2 as CD WR Momo , it's a valid rearrange after all. Fitting name for something that had a idol dating sim as a launch title.

schadenfreude

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Re: HuCard (Who Card or Hugh Card) You decide!
« Reply #66 on: February 14, 2017, 03:24:20 PM »
If you assume it's one single variable ie: ("ROM")2, you would get ROMROM.

Which is what the Japanese did.

I was making a joke about how the individual letters look like part of a math equation, such as "E = mc2". What I was getting at is that the M variable is the one that is raised to the second power, not the others. If it had been written as "(ROM)2" with parentheses around ROM, then yes, the entire expression would be squared, and the result would be "ROMROM". But without the parentheses, only the M is squared, and thus the result is "ROMM".

But anyway, this is all silly because it's clear that they wanted to double "ROM" since they see those three letters as one unit, not individual variables.

Arkhan

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Re: HuCard (Who Card or Hugh Card) You decide!
« Reply #67 on: February 14, 2017, 03:47:51 PM »
(sequences of syllables or letters), and so mathematical rules cannot possibly apply in a logical way.

mmmm.... careful, lol.

Calculus loves them some sequences of letters and shit.   :)


It seems fair that if they're treating ROM as one word unit, as we all do.  (seriously, if you say CD Are Oh Emm, you are a tool and should never open your face again)

So since it's one unit, squaring it works.   It's really no different than any other substitution crap used in Calculus with exponents.

we have X^2, squiggly greek letters ^ 2, why not have ROM^2 too. 

X^2 = XX, ROM^2 = ROMROM.

It all makes sense really.
[Fri 19:34]<nectarsis> been wanting to try that one for awhile now Ope
[Fri 19:33]<Opethian> l;ol huge dong

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ccovell

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Re: HuCard (Who Card or Hugh Card) You decide!
« Reply #68 on: February 14, 2017, 05:10:37 PM »
It all makes sense really.

You've got Japanese Stockholm syndrome already without ever having lived here; that's impressive.  ;-)